5x^2+9x-8360=0

Solution for 5x^2+9x-8360=0 equation:

5x^2+9x-8360=0

a = 5; b = 9; c = -8360;
Δ = b2-4ac
Δ = 92-4·5·(-8360)
Δ = 167281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{167281}=409$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-409}{2*5}=\frac{-418}{10}
=-41+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+409}{2*5}=\frac{400}{10}
=40
$